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JEE Main 22 Jan 2025 Sft-1Medium

Q.Let f:RRf : \mathbb{R} \to \mathbb{R} be a twice differentiable function such that f(x+y)=f(x)f(y)f(x + y) = f(x)f(y) for all x,yR. x, y \in \mathbb{R}. If f(0)=4af'(0) = 4a and ff satisfies f(x)3af(x)f(x)=0,a>0,f''(x) - 3a f'(x) - f(x) = 0, a > 0, then the area of the region R={(x,y)0yf(ax),0x2}R = \{(x,y) | 0 \le y \le f(ax), 0 \le x \le 2\} is:

a
e21e^{2} - 1
b
e4+1e^{4} + 1
c
e41e^{4} - 1
d
e2+1e^{2} + 1

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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