Home/Question #16210
JEE Main 22 Jan 2025 Sft-1Medium

Q.Let for f(x)=7tan8x+7tan6x3tan4x3tan2x,I1=0π/4f(x)dxf(x) = 7\tan^{8} x + 7\tan^{6} x - 3\tan^{4} x - 3\tan^{2} x, I_{1} = \int_{0}^{\pi/4} f(x) \, dx and I2=0π/4xf(x)dx.I_{2} = \int_{0}^{\pi/4} x f(x) \, dx. Then 7I1+12I27I_{1} + 12I_{2} is equal to:

a
2π2\pi
b
π\pi
c
1
d
2

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here