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JEE Main 22 Jan 2025 Sft-1Medium

Q.Uniform circular disc radius R mass M, small part radius R/2 removed. MI of remaining about perpendicular axis through centre

a
7/32MR27/32 MR^2
b
9/32MR29/32 MR^2
c
17/32MR217/32 MR^2
d
13/32MR213/32 MR^2

Correct Answer: Option D

The correct solution involves applying the fundamental concept to derive the final value step by step...

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