Home/Question #165
PracticeMedium

Q.The temperature at which the resistance of a conductor becomes 20% more than at 27°C is (α=0.004∘\alpha = 0.004^\circC−1^{-1})

a
50∘50^\circC
b
77∘77^\circC
c
100∘100^\circC
d
127∘127^\circC

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here