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Q.Let z=cosθ+isinθz = \cos \theta + i \sin \theta. Then the value of m=115Im(z2m1)\sum_{m=1}^{15} \operatorname{Im}(z^{2m-1}) at θ=2\theta = 2^\circ is

a
1sin2\frac{1}{\sin 2^\circ}
b
13sin2\frac{1}{3 \sin 2^\circ}
c
12sin2\frac{1}{2 \sin 2^\circ}
d
14sin2\frac{1}{4 \sin 2^\circ}

Correct Answer: Option D

The correct solution involves applying the fundamental concept to derive the final value step by step...

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