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Q.The number of distinct complex numbers zz satisfying the equation z+1ωω2 ωz+ω21 ω21z+ω=0\begin{vmatrix} z+1 & \omega & \omega^2 \ \omega & z+\omega^2 & 1 \ \omega^2 & 1 & z+\omega \end{vmatrix} = 0, where ω\omega is a cube root of unity (ω1\omega \ne 1), is

a
0
b
1
c
2
d
3

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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