Q.Let $z_1, z_2$ be complex numbers such that $|z_1 + z_2|^2 = |z_1|^2 + |z_2|^2$ . Then $\frac{z_1}{z_2}$ (assuming $z_2 \ne 0$ ) is

purely real

purely imaginary

zero

none of these

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.Let z1,z2z_1, z_2z1​,z2​ be complex numbers such that ∣z1+z2∣2=∣z1∣2+∣z2∣2|z_1 + z_2|^2 = |z_1|^2 + |z_2|^2∣z1​+z2​∣2=∣z1​∣2+∣z2​∣2. Then z1z2\frac{z_1}{z_2}z2​z1​​ (assuming z2≠0z_2 \ne 0z2​=0) is