Q.If $z$ is a non-zero complex number such that $\arg(z) = \frac{\pi}{6}$ and $\arg(z-1) = \frac{\pi}{3}$ , then $z$ lies on

a straight line

a circle

an ellipse

none

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.If zzz is a non-zero complex number such that arg⁡(z)=π6\arg(z) = \frac{\pi}{6}arg(z)=6π​ and arg⁡(z−1)=π3\arg(z-1) = \frac{\pi}{3}arg(z−1)=3π​, then zzz lies on