Q.Let $\alpha, \beta$ be the roots of the equation $z^2 - (p+2)z + (p+5) = 0$ where $p \in \mathbb{R}$ . If $\alpha^2 + \beta^2 = \alpha\beta$ , then $p$ equals

-3

-1

The correct solution involves applying the fundamental concept to derive the final value step by step...

Already a member? Login here

Q.Let α,β\alpha, \betaα,β be the roots of the equation z2−(p+2)z+(p+5)=0z^2 - (p+2)z + (p+5) = 0z2−(p+2)z+(p+5)=0 where p∈Rp \in \mathbb{R}p∈R. If α2+β2=αβ\alpha^2 + \beta^2 = \alpha\betaα2+β2=αβ, then ppp equals