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Q.If zz satisfies z+zˉ=2Re(z)z + \bar{z} = 2\operatorname{Re}(z) and z22i=1|z - 2 - 2i| = 1, then zz is

a
2+i2+i
b
3+i3+i
c
2+3i2+3i
d
1+i1+i

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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