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Q.If ∣z+3i∣≤2|z+3i| \le 2 and z=x+iyz = x + iy, then maximum value of x+yx + y is

a
3+223 + 2\sqrt{2}
b
3−223 - 2\sqrt{2}
c
2+322 + 3\sqrt{2}
d
none

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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If |z+3i| \le 2 and z = x + iy, then maximum value of x... | ParikshaNiti