Q.If $z$ satisfies $|z^2 - 1| = |z|^2$ , then $z$ lies on

real axis

imaginary axis

unit circle

circle centre origin

The correct solution involves applying the fundamental concept to derive the final value step by step...

Already a member? Login here

Q.If zzz satisfies ∣z2−1∣=∣z∣2|z^2 - 1| = |z|^2∣z2−1∣=∣z∣2, then zzz lies on