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Q.If the roots of the equation (x2+px+q)(x2+rx+s)=0(x^2 + px + q)(x^2 + rx + s) = 0 are equal in magnitude but opposite in sign, then q+s=q + s =

a
0
b
p+rp + r
c
prqspr - qs
d
pqrspq - rs

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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