Home/Question #1928
PracticeMedium

Q.If an=1⋅3⋅5⋯(2n−1)2⋅4⋅6⋯2na_n = \dfrac{1 \cdot 3 \cdot 5 \cdots (2n-1)}{2 \cdot 4 \cdot 6 \cdots 2n}, then a1+a2+⋯+an=a_1 + a_2 + \cdots + a_n =

a
n2n+1\dfrac{n}{2n+1}
b
n+12(n+1)+1\dfrac{n+1}{2(n+1)+1}
c
2n+12n\dfrac{2n+1}{2n}
d
n2n−1\dfrac{n}{2n-1}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here

If an = \dfrac{1 \cdot 3 \cdot 5 \cdots (2n-1)}{2 \cdot 4 ... | ParikshaNiti