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Q.The sum ∑k=1nk2k\sum_{k=1}^{n} \dfrac{k}{2^k} equals

a
n−21−nn - 2^{1-n}
b
2(n−21−n)2(n - 2^{1-n})
c
n+21−nn + 2^{1-n}
d
2(n+21−n)2(n + 2^{1-n})

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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