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Q.The sum of the series 910+99100+9991000+⋯\dfrac{9}{10} + \dfrac{99}{100} + \dfrac{999}{1000} + \cdots to nn terms is

a
10(10n−19⋅10n)10(\dfrac{10^n - 1}{9 \cdot 10^n})
b
10−n10n10 - \dfrac{n}{10^n}
c
9n−10+110n−19n - 10 + \dfrac{1}{10^{n-1}}
d
10n−9+110n−110n - 9 + \dfrac{1}{10^{n-1}}

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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