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Q.The sum ∑k=1n(nk)k2\sum_{k=1}^{n} \binom{n}{k} k^2 equals

a
n⋅2n−1n \cdot 2^{n-1}
b
n(n+1)2n−2n(n+1)2^{n-2}
c
n(n−1)2n−2+n2n−1n(n-1)2^{n-2} + n2^{n-1}
d
n22n−1n^2 2^{n-1}

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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