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Q.The sum of 20 terms of the series cosα+(cosαcosβ+sinαsinβ)+(cosαcos2β+sinαsin2β)+\cos \alpha + (\cos \alpha \cos \beta + \sin \alpha \sin \beta) + (\cos \alpha \cos 2\beta + \sin \alpha \sin 2\beta) + \cdots is

a
sin10βsinβcos(α+9β)\dfrac{\sin 10\beta}{\sin \beta} \cos (\alpha + 9\beta)
b
sin20βsinβcos(α+9β)\dfrac{\sin 20\beta}{\sin \beta} \cos (\alpha + 9\beta)
c
sin10β2sinβcos(α+9β)\dfrac{\sin 10\beta}{2\sin \beta} \cos (\alpha + 9\beta)
d
sin20β2sinβcos(α+10β)\dfrac{\sin 20\beta}{2\sin \beta} \cos (\alpha + 10\beta)

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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