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Q.The sum ∑k=0n(nk)(−1)k1k+1\sum_{k=0}^{n} \binom{n}{k} (-1)^k \dfrac{1}{k+1} equals

a
1n+1\dfrac{1}{n+1}
b
(−1)n1n+1(-1)^n \dfrac{1}{n+1}
c
(−1)nn+1\dfrac{(-1)^n}{n+1}
d
1n\dfrac{1}{n}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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