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Q.The sum of the series 0.4+0.44+0.444+⋯0.4 + 0.44 + 0.444 + \cdots to nn terms is

a
49(10n−1)−4n9\dfrac{4}{9} \left(10^n - 1\right) - \dfrac{4n}{9}
b
49n−481(10n−1)\dfrac{4}{9}n - \dfrac{4}{81}(10^n - 1)
c
49(n−19(10n−1))\dfrac{4}{9} \left(n - \dfrac{1}{9}(10^n - 1)\right)
d
49(n−10n−19)\dfrac{4}{9} \left(n - \dfrac{10^n - 1}{9}\right)

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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