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भौतिकशास्त्र - प्रकाशMedium

Q.क्रांतिक कोन (critical angle) चे सूत्र काय?

a
sinC=1n \sin C = \frac{1}{n} (दाट ते विरळ माध्यमासाठी)
b
sinC=n \sin C = n
c
C=sinn C = \sin n
d
C=90° C = 90°

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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