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Q.The number of ways of arranging 6 boys and 4 girls in a row such that no two girls are together is

a
6!×P(7,4)6! × P(7,4)
b
6!×(74)×4!6! × \binom{7}{4} × 4!
c
7!×4!7! × 4!
d
10!/(6!4!)10! / (6!4!)

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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