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Q.The number of ways of arranging 5 boys and 5 girls in a row such that no two girls are together is

a
5!×P(6,5)5! × P(6,5)
b
5!×(65)×5!5! × \binom{6}{5} × 5!
c
10!/(5!5!)10! / (5!5!)
d
5!×6!5! × 6!

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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