Q.The number of ways to divide 12 distinct students into two groups of 6 each for a debate competition (groups are unlabelled) is

\dfrac{\binom{12}{6}}{2}

\binom{12}{6}

\dfrac{\binom{12}{6} × 6! × 6!}{12!}

\dfrac{12!}{(6!)^2}

The correct solution involves applying the fundamental concept to derive the final value step by step...

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