Q.The number of ways of distributing 10 distinct books to 3 students such that each gets at least 2 books is

3^{10} - 3 × 2^{10} + 3 × 1^{10}

3! {10 \brace 3}

3^{10} - 3 × 2^{10}

3! S(10,3)

The correct solution involves applying the fundamental concept to derive the final value step by step...

Already a member? Login here