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Q.The number of ways of colouring 6 beads of a necklace with 3 colours such that no two adjacent beads have the same colour and beads can be flipped is

a
3×25+3×233 × 2^5 + 3 × 2^3
b
(3×25+3)/6(3 × 2^5 + 3)/6
c
42
d
54

Correct Answer: Option D

The correct solution involves applying the fundamental concept to derive the final value step by step...

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