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Q.The number of ways to divide 12 distinct players into two teams of 6 each such that two particular players are in different teams is

a
(126)2\dfrac{\binom{12}{6}}{2}
b
(105)\binom{10}{5}
c
2×(105)2 × \binom{10}{5}
d
(106)\binom{10}{6}

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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