Home/Question #2058
PracticeMedium

Q.The number of ways of arranging 4 red, 5 green and 6 blue identical balls in a row such that no two red balls are adjacent is

a
(124)×(85)\binom{12}{4} × \binom{8}{5}
b
(114)×(75)\binom{11}{4} × \binom{7}{5}
c
(126)×(64)\binom{12}{6} × \binom{6}{4}
d
(134)\binom{13}{4}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here