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Q.If (1+x+x2+x3)16=r=048arxr(1 + x + x^2 + x^3)^{16} = \sum_{r=0}^{48} a_r x^r, then a0+a4+a8++a48a_0 + a_4 + a_8 + \cdots + a_{48} equals

a
2152^{15}
b
2162^{16}
c
2312^{31}
d
2322^{32}

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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