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Q.If (1+x)15=∑r=015(15r)xr(1 + x)^{15} = \sum_{r=0}^{15} \binom{15}{r} x^r, then ∑r=07(−1)r(15r)=\sum_{r=0}^{7} (-1)^r \binom{15}{r} =

a
(147)\binom{14}{7}
b
(157)\binom{15}{7}
c
(158)\binom{15}{8}
d
00

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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