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Q.If (1+3x−2x2)n=∑r=02narxr(1 + 3x - 2x^2)^n = \sum_{r=0}^{2n} a_r x^r, then a0+a2+a4+⋯a_0 + a_2 + a_4 + \cdots equals

a
3n3^n
b
2n2^n
c
(−1)n(-1)^n
d
2n−1(3n+1)2^{n-1} (3^n + 1)

Correct Answer: Option D

The correct solution involves applying the fundamental concept to derive the final value step by step...

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If (1 + 3x - 2x^2)^n = \sum{r=0}^{2n} ar x^r, then a0 ... | ParikshaNiti