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Q.If (1+x)20+(1+x)21++(1+x)30=r=0karxr(1 + x)^{20} + (1 + x)^{21} + \cdots + (1 + x)^{30} = \sum_{r=0}^{k} a_r x^r, then a0+a1+a2++a10a_0 + a_1 + a_2 + \cdots + a_{10} equals

a
1123011 \cdot 2^{30}
b
112(2311)\dfrac{11}{2} (2^{31} - 1)
c
112301111 \cdot 2^{30} - 11
d
112(231+1)\dfrac{11}{2} (2^{31} + 1)

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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