Q.If the ratio of the 5th term from the beginning to the 5th term from the end in the expansion of $(2^{1/3} + \dfrac{1}{2^{1/4}})^{12}$ is $\sqrt{6} : 1$ , then the 7th term from the beginning is

\binom{12}{6} 2^{8/3}

\binom{12}{6} 2^{10/3}

\binom{12}{6} 2^{4}

\binom{12}{6} 2^{14/3}

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.If the ratio of the 5th term from the beginning to the 5th term from the end in the expansion of (21/3+121/4)12(2^{1/3} + \dfrac{1}{2^{1/4}})^{12}(21/3+21/41​)12 is 6:1\sqrt{6} : 16​:1, then the 7th term from the beginning is