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Q.If (1+x)n=∑k=0nckxk(1 + x)^{n} = \sum_{k=0}^{n} c_k x^k, then c0+c2+c4+⋯c_0 + c_2 + c_4 + \cdots equals

a
2n−12^{n-1}
b
2n2^n
c
2n+(1+(−1)n)/22\dfrac{2^n + (1+(-1)^n)/2}{2}
d
2n−1+2n−22\dfrac{2^{n-1} + 2^{n-2}}{2}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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