Home/Question #2130
PracticeMedium

Q.The value of ∑k=1nk3(nk)\sum_{k=1}^{n} k^3 \binom{n}{k} is

a
n(n+1)2n−1n(n+1)2^{n-1}
b
n2(n+1)2n−2n^2 (n+1) 2^{n-2}
c
n(n+1)(n+2)(n+3)2n−4n(n+1)(n+2)(n+3)2^{n-4}
d
n(n+1)2nn(n+1)2^{n}

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here