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Q.The system of equations x+y+z=6x + y + z = 6, x+2y+3z=10x + 2y + 3z = 10, x+2y+λz=μx + 2y + \lambda z = \mu has no solution if

a
λ=3,μ≠10\lambda = 3, \mu \ne 10
b
λ=3,μ=10\lambda = 3, \mu = 10
c
λ≠3\lambda \ne 3
d
λ=3\lambda = 3 only

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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