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Q.The inverse of the matrix (123 014 001)\begin{pmatrix} 1 & 2 & 3 \ 0 & 1 & 4 \ 0 & 0 & 1 \end{pmatrix} is

a
(1−2−5 01−4 001)\begin{pmatrix} 1 & -2 & -5 \ 0 & 1 & -4 \ 0 & 0 & 1 \end{pmatrix}
b
(1−25 01−4 001)\begin{pmatrix} 1 & -2 & 5 \ 0 & 1 & -4 \ 0 & 0 & 1 \end{pmatrix}
c
(12−5 01−4 001)\begin{pmatrix} 1 & 2 & -5 \ 0 & 1 & -4 \ 0 & 0 & 1 \end{pmatrix}
d
(1−25 014 001)\begin{pmatrix} 1 & -2 & 5 \ 0 & 1 & 4 \ 0 & 0 & 1 \end{pmatrix}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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