Q.If $A = \begin{pmatrix} 1 & 1 & 1 \ 1 & \omega & \omega^2 \ 1 & \omega^2 & \omega \end{pmatrix}$ where $\omega$ is cube root of unity, then $\det A$ equals

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Q.If A=(111 1ωω2 1ω2ω)A = \begin{pmatrix} 1 & 1 & 1 \ 1 & \omega & \omega^2 \ 1 & \omega^2 & \omega \end{pmatrix}A=(1​1​1 1​ω​ω2 1​ω2​ω​) where ω\omegaω is cube root of unity, then det⁡A\det AdetA equals