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Q.The system kx+y+z=1kx + y + z = 1, x+ky+z=kx + ky + z = k, x+y+kz=k2x + y + kz = k^2 has no solution if

a
k=1k=1
b
k=1k=-1
c
k=0k=0
d
k=2k=2

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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