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Q.If A=(111 1ωω2 1ω2ω)A = \begin{pmatrix} 1 & 1 & 1 \ 1 & \omega & \omega^2 \ 1 & \omega^2 & \omega \end{pmatrix} where ω\omega is a primitive cube root of unity, then A3A^{3} equals

a
I
b
3I
c
0
d
3A

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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