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Q.If A=(010 001 −12−11−6)A = \begin{pmatrix} 0 & 1 & 0 \ 0 & 0 & 1 \ -12 & -11 & -6 \end{pmatrix}, then A100A^{100} is

a
(0100(1002) 00100 000)\begin{pmatrix} 0 & 100 & \binom{100}{2} \ 0 & 0 & 100 \ 0 & 0 & 0 \end{pmatrix}
b
(11004950 01100 001)\begin{pmatrix} 1 & 100 & 4950 \ 0 & 1 & 100 \ 0 & 0 & 1 \end{pmatrix}
c
similar to Jordan form powers
d
none

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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