Q.If $P(A \cup B) = P(A \cap B)$ , then

P(A) + P(B) = 1

P(A) = P(B)

A

and

B

are mutually exclusive

A

and

B

are independent

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.If P(A∪B)=P(A∩B)P(A \cup B) = P(A \cap B)P(A∪B)=P(A∩B), then