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Q.A random variable XX has the following probability distribution: XX | 0 1 2 3 4 5 6 P(X)P(X) | kk 3k3k 5k5k 7k7k 9k9k 11k11k 13k13k Then P(X3)P(X \ge 3) equals

a
4049\dfrac{40}{49}
b
4149\dfrac{41}{49}
c
4249\dfrac{42}{49}
d
4349\dfrac{43}{49}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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