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Q.If XX is a binomial variate with parameters nn and pp, then E(1X+1)E(\dfrac{1}{X+1}) equals

a
1−pn+1\dfrac{1-p}{n+1}
b
1−(1−p)n+1(n+1)p\dfrac{1 - (1-p)^{n+1}}{(n+1)p}
c
(1−p)n+1n+1\dfrac{(1-p)^{n+1}}{n+1}
d
qn+1n+1\dfrac{q^{n+1}}{n+1}

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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