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Q.If X∼B(10,1/3)X \sim B(10, 1/3), then P(X=4)P(X=4) equals

a
10!4!6!(13)4(23)6\dfrac{10!}{4!6!} \left(\dfrac{1}{3}\right)^4 \left(\dfrac{2}{3}\right)^6
b
(104)⋅26310\dfrac{\binom{10}{4} \cdot 2^6}{3^{10}}
c
(106)⋅24310\dfrac{\binom{10}{6} \cdot 2^4}{3^{10}}
d
(104)⋅24310\dfrac{\binom{10}{4} \cdot 2^4}{3^{10}}

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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