Q.If $f(x) = \begin{cases} x^2 & x \le 0 \ |x| & x > 0 \end{cases}$ , then $f$ is

continuous at

x=0

discontinuous at

x=0

not differentiable at

x=0

both (a) and (c)

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.If f(x)={x2x≤0 ∣x∣x>0f(x) = \begin{cases} x^2 & x \le 0 \ |x| & x > 0 \end{cases}f(x)={x2​x≤0 ∣x∣​x>0​, then fff is