The function $f(x) = \begin{cases} x + 1 & x 3 \end{cases}$ is

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Q.The function $f(x) = \begin{cases} x + 1 & x < 1 \ 3 - x & 1 \le x \le 3 \ x - 3 & x > 3 \end{cases}$ is

continuous everywhere

continuous except at

x=1

and

x=3

continuous except at

x=3

discontinuous everywhere

The correct solution involves applying the fundamental concept to derive the final value step by step...

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