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Q.If f(x)={xsin(1/x)x0 0x=0f(x) = \begin{cases} x \sin(1/x) & x \ne 0 \ 0 & x = 0 \end{cases}, then ff is

a
continuous but not differentiable at x=0x=0
b
differentiable at x=0x=0
c
discontinuous at x=0x=0
d
none

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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If f(x) = \begin{cases} x \sin(1/x) & x \ne 0 \\ 0 & x = 0 ... | ParikshaNiti