Q.The function $f(x) = \dfrac{\ln(1+x)}{x}$ $(f(0)=1)$ is

continuous and differentiable on

\mathbb{R}

continuous on

\mathbb{R}

but not differentiable at

x=0

continuous on

(-1,\infty)

and differentiable on

(-1,0) \cup (0,\infty)

none

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The function f(x)=ln⁡(1+x)xf(x) = \dfrac{\ln(1+x)}{x}f(x)=xln(1+x)​ (f(0)=1)(f(0)=1)(f(0)=1) is