Q.The function $f(x) = \begin{cases} e^{1/x} & x \ne 0 \ 0 & x = 0 \end{cases}$ has

removable discontinuity at

x=0

infinite discontinuity at

x=0

jump discontinuity at

x=0

continuous at

x=0

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The function f(x)={e1/xx≠0 0x=0f(x) = \begin{cases} e^{1/x} & x \ne 0 \ 0 & x = 0 \end{cases}f(x)={e1/x​x=0 0​x=0​ has